C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t, b\u00ed k\u00edp b\u1eaft \u0111\u1ec1 d\u1ec5 \u0103n nh\u1ea5t, \u0111\u01a1n gi\u1ea3n v\u00e0 d\u1ec5 d\u00e0ng cho anh em m\u1edbi ch\u01a1i. \u00c1p d\u1ee5ng c\u00e1ch \u0111\u00e1nh n\u00e0y gi\u00fap t\u0103ng kh\u1ea3 n\u0103ng th\u1eafng gi\u1ea3i trong ng\u00e0y h\u00f4m sau<\/p>\n
B\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00e0 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u ch\u1ed1t s\u1ed1 c\u00f3 hi\u1ec7u qu\u1ea3 c\u1ef1c t\u1ed1t th\u01b0\u1eddng \u0111\u01b0\u1ee3c anh em l\u00f4 th\u1ee7 \u00e1p d\u1ee5ng. Anh em tham gia ch\u01a1i b\u1eb1ng c\u00e1ch n\u00e0y ph\u1ea3i c\u00f3 suy lu\u1eadn s\u00e1ng su\u1ed1t \u0111\u1ec3 c\u00f3 th\u1ec3 b\u1eaft \u0111\u01b0\u1ee3c con \u0111\u1ec1 tr\u00fang. Ch\u00fang t\u00f4i s\u1ebd b\u1eadt m\u00ed cho anh em c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t hay nh\u1ea5t t\u1eeb c\u00e1c cao th\u1ee7.<\/p>\n
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t<\/h3>\n
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L\u00e0 c\u00e1ch ch\u1ed1t s\u1ed1 \u0111\u1ec1 c\u1ee7a h\u00f4m sau d\u1ef1a v\u00e0o gi\u1ea3i \u0111\u1eb7c bi\u1ec7t trong b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y h\u00f4m nay. C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t kh\u00e1 ph\u1ed5 bi\u1ebfn v\u1edbi c\u00e1c anh em ch\u01a1i x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc. B\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t c\u00f3 th\u1ec3 k\u1ebft h\u1ee3p v\u1edbi nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u kh\u00e1c soi c\u1ea7u b\u1ea1c nh\u1edb,c\u1ea7u ch\u1eb5n l\u1ebb,\u2026 \u0111\u1ec3 \u0111\u01b0a ra quy\u1ebft \u0111\u1ecbnh ch\u00ednh x\u00e1c h\u01a1n. Anh em c\u00f3 th\u1ec3 \u00e1p d\u1ee5ng m\u1ed9t s\u1ed1 ph\u01b0\u01a1ng ph\u00e1p m\u00e0 ch\u00fang t\u00f4i g\u1ee3i \u00fd d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n
C\u1ed9ng d\u1ed3n c\u00e1c gi\u1ea3i \u0111\u1eb7c bi\u1ec7t \u0111\u00e3 v\u1ec1 nh\u1eefng ng\u00e0y tr\u01b0\u1edbc<\/h4>\n
Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ph\u00f9 h\u1ee3p v\u1edbi nh\u1eefng anh em c\u00f3 t\u00ednh nh\u1eabn n\u1ea1i cao. \u0110\u00fang nh\u01b0 c\u00e1ch g\u1ecdi th\u00ec anh em ch\u1ec9 c\u1ea7n c\u1ed9ng c\u00e1c gi\u1ea3i \u0111\u1eb7c bi\u1ec7t \u0111\u00e3 v\u1ec1 ng\u00e0y tr\u01b0\u1edbc \u0111\u1ec3 t\u1ea1o \u0111\u01b0\u1ee3c s\u1ed1 \u0111\u1ec1 cho m\u00ecnh. Sau khi c\u1ed9ng xong th\u00ec s\u1ebd \u0111\u01b0\u1ee3c 10 c\u1eb7p l\u00f4 nu\u00f4i trong 1 tu\u1ea7n. N\u1ebfu tr\u01b0\u1eddng h\u1ee3p c\u1ed9ng t\u1ed5ng \u0111\u01b0\u1ee3c l\u1edbn h\u01a1n 10 th\u00ec ch\u1ec9 ch\u1ecdn s\u1ed1 \u1edf h\u00e0ng \u0111\u01a1n v\u1ecb.<\/p>\n
B\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t theo gi\u1ea3i 7<\/h3>\n
\u1ede c\u00e1ch n\u00e0y anh em c\u1ed9ng t\u1ed5ng c\u1ee7a c\u1eb7p s\u1ed1 th\u1ee9 2 trong gi\u1ea3i 7 v\u00e0 d\u00f9ng s\u1ed1 n\u00e0y \u0111\u1ec3 nu\u00f4i trong ng\u00e0y ti\u1ebfp theo.<\/p>\n
V\u00ed d\u1ee5: C\u1eb7p s\u1ed1 th\u1ee9 2 trong gi\u1ea3i 7 l\u00e0 80, c\u1ed9ng s\u1ed1 l\u1ea1i s\u1ebd \u0111\u01b0\u1ee3c t\u1ed5ng 8. Anh em l\u1ea5y 9 l\u00e0m b\u1ea1ch th\u1ee7 l\u00f4 \u0111\u1ec3 \u0111\u00e1nh trong ng\u00e0y ti\u1ebfp theo. Ho\u1eb7c l\u1ea5y c\u1eb7p song th\u1ee7 l\u00f4 09 \u2013 90 \u0111\u1ec3 nu\u00f4i trong 7 ng\u00e0y.<\/p>\n
V\u1edbi tr\u01b0\u1eddng h\u1ee3p t\u1ed5ng s\u1ed1 c\u1eb7p th\u1ee9 2 trong gi\u1ea3i 7 l\u1edbn h\u01a1n 10: C\u1eb7p s\u1ed1 th\u1ee9 2 trong gi\u1ea3i 7 l\u00e0 67, s\u1ebd c\u00f3 t\u1ed5ng l\u00e0 13. Anh em b\u1eaft t\u1ed5ng \u0111\u1ec1 l\u00e0 1 + 3 v\u00e0 1 \u2013 3, s\u1ebd c\u00f3 2 t\u1ed5ng \u0111\u1ec1 l\u00e0 4 v\u00e0 2 \u0111\u1ec3 nu\u00f4i cho ng\u00e0y sau.<\/p>\n
C\u00e1ch \u0111\u00e1nh n\u00e0y nhanh g\u1ecdn, s\u1ed1 v\u1ec1 trong tu\u1ea7n v\u00e0 th\u00edch h\u1ee3p c\u1ea3 v\u1edbi XSMB v\u00e0 XSMN.<\/p>\n
B\u1eaft t\u1ed5ng \u0111\u1ec1 b\u1eb1ng tam gi\u00e1c Pascal<\/h3>\n
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B\u01b0\u1edbc \u0111\u1ea7u ti\u00ean, anh em ph\u1ea3i l\u1ea5y gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 gi\u1ea3i nh\u1ea5t \u0111\u00e3 v\u1ec1 h\u00f4m nay \u0111\u1ec3 t\u1ea1o \u0111\u00e1y c\u1ee7a tam gi\u00e1c.<\/p>\n
V\u00ed d\u1ee5: Gi\u1ea3i \u0111\u1eb7c bi\u1ec7t h\u00f4m nay l\u00e0 31458 v\u00e0 gi\u1ea3i nh\u1ea5t l\u00e0 5647. Gh\u00e9p 2 gi\u1ea3i n\u00e0y v\u1edbi nhau theo th\u1ee9 t\u1ef1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t \u0111\u1ebfn gi\u1ea3i nh\u1ea5t s\u1ebd \u0111\u01b0\u1ee3c h\u00e0ng: 3 \u2013 1 \u2013 4 \u2013 5 \u2013 8 \u2013 5 \u2013 6 \u2013 4 \u2013 7 \u1edf \u0111\u00e1y c\u1ee7a tam gi\u00e1c. Sau \u0111\u00f3 s\u1eed d\u1ee5ng kh\u00e1i ni\u1ec7m tam gi\u00e1c Pascal:<\/p>\n
C\u1ed9ng 2 s\u1ed1 trong d\u00e3y v\u1eeba t\u1ea1o theo th\u1ee9 t\u1ef1 t\u1eeb tr\u00e1i sang ph\u1ea3i s\u1ebd \u0111\u01b0\u1ee3c h\u00e0ng ti\u1ebfp theo c\u1ee7a tam gi\u00e1c: 3+1=4, 4+5=9, 8+5=13 l\u1ea5y 3, 6+4=10 l\u1ea5y 0, 4+7=11 l\u1ea5y 1 \u0111\u01b0\u1ee3c h\u00e0ng ti\u1ebfp theo: 4 \u2013 9 \u2013 3 \u2013 0 \u2013 1<\/p>\n
Ti\u1ebfp t\u1ee5c c\u1ed9ng nh\u01b0 v\u1eady v\u1edbi h\u00e0ng ti\u1ebfp theo \u0111\u1ebfn khi l\u00ean \u0111\u1ec9nh c\u1ee7a tam gi\u00e1c, con s\u1ed1 cu\u1ed1i c\u00f9ng \u1edf \u0111\u1ec9nh s\u1ebd \u0111\u01b0\u1ee3c l\u00e0m c\u1eb7p song th\u1ee7 v\u00e0 nu\u00f4i trong v\u00f2ng 7 ng\u00e0y.<\/p>\n
Nhi\u1ec1u anh em hay nh\u1ea7m gi\u1eefa ph\u01b0\u01a1ng ph\u00e1p n\u00e0y v\u00e0 ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u tam gi\u00e1c. Tuy nhi\u00ean 2 c\u00e1ch n\u00e0y l\u00e0 ho\u00e0n to\u00e0n kh\u00e1c nhau. Anh em l\u01b0u \u00fd khi s\u1eed d\u1ee5ng ph\u01b0\u01a1ng ph\u00e1p n\u00e0y th\u00ec ph\u1ea3i theo d\u00f5i v\u00e0 lo\u1ea1i b\u1ecf nh\u1eefng con l\u00f4 gan.<\/p>\n
B\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t theo b\u1ea1c nh\u1edb<\/h3>\n
Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u01b0\u1ee3c nhi\u1ec1u anh em tin t\u01b0\u1edfng l\u1ef1a ch\u1ecdn. Theo nh\u1eefng tay l\u00f4 th\u1ee7 chuy\u00ean nghi\u1ec7p th\u00ec \u0111\u00e2y l\u00e0 c\u00e1ch soi c\u1ea7u kh\u00e1 an to\u00e0n. Anh em ch\u01a1i l\u00f4 \u0111\u1ec1 l\u00e2u n\u0103m \u0111\u1ec1u b\u1eaft t\u1ed5ng \u0111\u1eb7c bi\u1ec7t theo c\u00e1ch n\u00e0y. M\u1ed9t s\u1ed1 quy lu\u1eadt \u0111\u01b0\u1ee3c \u0111\u00fac r\u00fat t\u1eeb kinh nghi\u1ec7m c\u1ee7a c\u00e1c ti\u1ec1n b\u1ed1i cho anh em tham kh\u1ea3o:<\/p>\n
N\u1ebfu t\u1ed5ng \u0111\u1eb7c bi\u1ec7t XSMB l\u00e0 9 th\u00ec h\u00f4m sau s\u1ebd v\u1ec1 t\u1ed5ng 5<\/p>\n
N\u1ebfu t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00e0 10 th\u00ec h\u00f4m sau d\u1ec5 v\u1ec1 t\u1ed5ng 1<\/p>\n
N\u1ebfu t\u1ed5ng \u0111\u1eb7c bi\u1ec7t l\u00e0 6 th\u00ec h\u00f4m sau d\u1ec5 v\u1ec1 t\u1ed5ng 8<\/p>\n
Th\u1ee9 2 hay v\u1ec1 c\u00e1c t\u1ed5ng \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t: 2, 8<\/p>\n
Th\u1ee9 3 hay v\u1ec1 c\u00e1c t\u1ed5ng \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t 1, 7<\/p>\n
Th\u1ee9 4 hay v\u1ec1 c\u00e1c t\u1ed5ng \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t 0, 7<\/p>\n
Th\u1ee9 5 hay v\u1ec1 c\u00e1c t\u1ed5ng \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t l\u00e0 2, 6<\/p>\n
Th\u1ee9 6 hay v\u1ec1 c\u00e1c t\u1ed5ng \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t l\u00e0 3, 4<\/p>\n
Th\u1ee9 7 hay v\u1ec1 c\u00e1c t\u1ed5ng \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t l\u00e0 1, 7<\/p>\n
Ch\u1ee7 nh\u1eadt hay v\u1ec1 c\u00e1c t\u1ed5ng \u0111\u1eb7c bi\u1ec7t 5, 8<\/p>\n
Tr\u00ean \u0111\u00e2y l\u00e0 nh\u1eefng c\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 \u0111\u1eb7c bi\u1ec7t hay nh\u1ea5t d\u00e0nh cho anh em m\u1edbi ch\u01a1i ho\u1eb7c c\u00f2n \u00edt kinh nghi\u1ec7m khi ch\u01a1i l\u00f4 \u0111\u1ec1. Anh em l\u01b0u \u00fd khi \u0111\u1eb7t c\u01b0\u1ee3c ch\u00fa \u00fd ph\u00e2n chia v\u1ed1n h\u1ee3p l\u00fd v\u00ec nh\u1eefng c\u00e1ch ch\u01a1i tr\u00ean \u0111\u1ec1u nu\u00f4i theo khung ng\u00e0y, tr\u00e1nh tr\u01b0\u1eddng h\u1ee3p v\u1ed1n h\u1ebft m\u00e0 \u0111\u1ec1 l\u1ea1i v\u1ec1. Ch\u00fac anh em may m\u1eafn!!!<\/p>\n<\/div>\n<\/div>\n